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2004-12-16 by gutman75
A chorused layer takes up twice the polyphony, because it utilises two detuned oscillators. A layer with 12-order filter takes up twice the polyphony. So, a chorused layer with 12-order filter takes up 4 times the polyphony? This always has been obvious for me, but yesterday I thought that maybe, somehow the two oscillators are able to share the filter? Sorry if it's a stupid question, I just want to make sure.
2004-12-16 by erik_magrini@Baxter.com
Don't forget that each preset actually has 4 layers, not two oscillators.
So if you use a preset with 4 layers of 12th order filters and chorus,
each key press with use up 12 notes of poly. Link three of these presets
together and you can only press 3 keys before running out of poly. :)
rEalm
gutman75 <bgutman@...>
12/16/2004 08:12 AM
Please respond to xl7
To: xl7@yahoogroups.com
cc: Subject: [xl7] polyphony question A chorused layer takes up twice the polyphony, because it utilises two detuned oscillators. A layer with 12-order filter takes up twice the polyphony. So, a chorused layer with 12-order filter takes up 4 times the polyphony? This always has been obvious for me, but yesterday I thought that maybe, somehow the two oscillators are able to share the filter? Sorry if it's a stupid question, I just want to make sure. Yahoo! Groups Links The information transmitted is intended only for the person(s)or entity to which it is addressed and may contain confidential and/or legally privileged material. Delivery of this message to any person other than the intended recipient(s) is not intended in any way to waive privilege or confidentiality. Any review, retransmission, dissemination or other use of , or taking of any action in reliance upon, this information by entities other than the intended recipient is prohibited. If you receive this in error, please contact the sender and delete the material from any computer. For Translation: http://www.baxter.com/email_disclaimer [Non-text portions of this message have been removed]
2004-12-16 by erik_magrini@Baxter.com
I mean 4 keys, math was never my strong point :)
Link three of these presets
together and you can only press 3 keys before running out of poly. :)
rEalm
gutman75 <bgutman@...>
12/16/2004 08:12 AM
Please respond to xl7
To: xl7@yahoogroups.com
cc: Subject: [xl7] polyphony question A chorused layer takes up twice the polyphony, because it utilises two detuned oscillators. A layer with 12-order filter takes up twice the polyphony. So, a chorused layer with 12-order filter takes up 4 times the polyphony? This always has been obvious for me, but yesterday I thought that maybe, somehow the two oscillators are able to share the filter? Sorry if it's a stupid question, I just want to make sure. Yahoo! Groups Links The information transmitted is intended only for the person(s)or entity to which it is addressed and may contain confidential and/or legally privileged material. Delivery of this message to any person other than the intended recipient(s) is not intended in any way to waive privilege or confidentiality. Any review, retransmission, dissemination or other use of , or taking of any action in reliance upon, this information by entities other than the intended recipient is prohibited. If you receive this in error, please contact the sender and delete the material from any computer. For Translation: http://www.baxter.com/email_disclaimer [Non-text portions of this message have been removed] Yahoo! Groups Links The information transmitted is intended only for the person(s)or entity to which it is addressed and may contain confidential and/or legally privileged material. Delivery of this message to any person other than the intended recipient(s) is not intended in any way to waive privilege or confidentiality. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by entities other than the intended recipient is prohibited. If you receive this in error, please contact the sender and delete the material from any computer. For Translation: http://www.baxter.com/email_disclaimer [Non-text portions of this message have been removed]
2004-12-16 by Aaron Eppolito
Actually, it's *2* keys, because a chorused voice with a 12th order filter uses 4 voices, not 3. "2 voices" x "2 12th order penalty" x "4 layers" x "3 linked" = 48 voices per note! And no, they can't share the filter because one osc is panned left and the other right, thus needing separate filter paths to keep the signals separate. -Aaron --- erik_magrini@... wrote: > > I mean 4 keys, math was never my strong point :) > > Link three of these presets > together and you can only press 3 keys before running out of poly. > :) > > > A chorused layer takes up twice the polyphony, because it utilises > two detuned oscillators. > A layer with 12-order filter takes up twice the polyphony. > So, a chorused layer with 12-order filter takes up 4 times the > polyphony? This always has been obvious for me, but yesterday I > thought that maybe, somehow the two oscillators are able to share the > filter? > Sorry if it's a stupid question, I just want to make sure. __________________________________ Do you Yahoo!? Yahoo! Mail - 250MB free storage. Do more. Manage less. http://info.mail.yahoo.com/mail_250
2004-12-16 by erik_magrini@Baxter.com
Hey I was right, math really ISN'T my strong point. :)
rEalm
"Aaron Eppolito" <synthesis77@...>
12/16/2004 12:13 PM
Please respond to xl7
To: xl7@yahoogroups.com
cc: Subject: Re: [xl7] polyphony question Actually, it's *2* keys, because a chorused voice with a 12th order filter uses 4 voices, not 3. "2 voices" x "2 12th order penalty" x "4 layers" x "3 linked" = 48 voices per note! And no, they can't share the filter because one osc is panned left and the other right, thus needing separate filter paths to keep the signals separate. -Aaron --- erik_magrini@... wrote: > > I mean 4 keys, math was never my strong point :) > > Link three of these presets > together and you can only press 3 keys before running out of poly. > :) > > > A chorused layer takes up twice the polyphony, because it utilises > two detuned oscillators. > A layer with 12-order filter takes up twice the polyphony. > So, a chorused layer with 12-order filter takes up 4 times the > polyphony? This always has been obvious for me, but yesterday I > thought that maybe, somehow the two oscillators are able to share the > filter? > Sorry if it's a stupid question, I just want to make sure. __________________________________ Do you Yahoo!? Yahoo! Mail - 250MB free storage. Do more. Manage less. http://info.mail.yahoo.com/mail_250 Yahoo! Groups Links The information transmitted is intended only for the person(s)or entity to which it is addressed and may contain confidential and/or legally privileged material. Delivery of this message to any person other than the intended recipient(s) is not intended in any way to waive privilege or confidentiality. Any review, retransmission, dissemination or other use of, or taking of any action in reliance upon, this information by entities other than the intended recipient is prohibited. If you receive this in error, please contact the sender and delete the material from any computer. For Translation: http://www.baxter.com/email_disclaimer [Non-text portions of this message have been removed]
2004-12-17 by José Sáez
That explains why some of my patches don't produce any sound at all. They have eaten all the polyphony BEFORE i ever pressed a key. :) Jose ........ I'm NOT going to fix your computer. ........
----- Original Message -----
From: Aaron Eppolito
To: xl7@yahoogroups.com
Sent: Thursday, December 16, 2004 3:13 PM
Subject: Re: [xl7] polyphony question
Actually, it's *2* keys, because a chorused voice with a 12th order
filter uses 4 voices, not 3.
"2 voices" x "2 12th order penalty" x "4 layers" x "3 linked" = 48
voices per note!
And no, they can't share the filter because one osc is panned left and
the other right, thus needing separate filter paths to keep the signals
separate.
-Aaron
--- erik_magrini@... wrote:
>
> I mean 4 keys, math was never my strong point :)
>
> Link three of these presets
> together and you can only press 3 keys before running out of poly.
> :)
>
>
> A chorused layer takes up twice the polyphony, because it utilises
> two detuned oscillators.
> A layer with 12-order filter takes up twice the polyphony.
> So, a chorused layer with 12-order filter takes up 4 times the
> polyphony? This always has been obvious for me, but yesterday I
> thought that maybe, somehow the two oscillators are able to share the
> filter?
> Sorry if it's a stupid question, I just want to make sure.
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