Casio CZ/ VZ/ FZ - Pro Series

Hello,

The CZs envelope time depends on both the rate and the difference between
the levels.
It is like throwing a ball.  The time depends on the speed you threw it
and the distance to the destination.
The CZ manual says that if you were to draw the invelope, a Rate of 99
would be representet by an angle of nearly 90 degrees.  And a rate of 0
would not change the level at all.  The line would be perfectly
horizontal. (0 degrees).   

Please correct me if I make any errors here:

After some fact finding, you could use a calculator to find the "Rate" or
Time.


You could use a stopwatch to find out how the rate numbers relate to
Levels per second:

For instance: You could measure how long it takes a sound to go from full
loudness (99) to silence (0) at a rate of 50.
Divide the number of seconds (or fraction of a second) by 50 and you will
know how many Levels per second a rate number represents.

______      --- Rate angle (50)
             \                           99
                \                           \
                    \                         >Distance
                       \                     /
                          \                0
                             \
             |  <-Time->
               

You should take another measurement to confirm that the level (volume)
drops half as fast when the Rate is at 1.

As soon as you know how many levels per second that the "Rate" numbers
represent, you can use a calculator to get the right "Rate" value for the
Time you want.
Rate x Time =  Distance.   R x T = D

The formula for Rate is: Distance (number of levels) / Time = Rate   D /
T =R

Divide the change in envlope "level" by the time (in seconds) that you
want.   The divide this number by the "levels pre second" numbe that you
determined with your stopwatch.


Like I said: please let me know if my geometry is wrong on this.
On digital syntheiszers: You might have some inconsistency in the fastest
rates and the lowest levels.  
I hope this is of help.
Make a joyful noise,
Nathan

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