why linearize? .... maybe long and boring ... and maybe i don't understand?
2008-01-26 by evanj1969
maybe this is a rather odd question, but here goes. why does one wish to linearize? i "assume" that when this happens with QTR, the 50% patch reads half that of the 100%, and twice that of the 0%. so if i linearize Velvet Fine Art, my 50% patch would be much lower than that of my Epson Exhibition Fiber. is this why many create an ICC to softproof with is Photoshop? the way i have always handled setting levels is as followed. 1.there is some basic overall adjustment to the density levels to achieve an approximate level described in #3. 2.use the R/G/B channels in PS to get my individual tones where i want them (using say UT-3D), to achieve a neutral tone (if that is the one desired) 3.once #2 is done (to my satisfaction, and there is usually some going back and forth), i adjust the level of my digital Q-13 according to my "understanding of the following. The Gray Scale, illustrated below, has densities from 0.05 to 1.95 in twenty steps of 0.1 (1/3 f-stop), labeled 0 (A) through 19. (Recall, density = -log10(reflected light/incident light.) Density = 0.05 is the reflectivity of white paper: about 90%. The step charts for gamma = 1.8 and 2.2 (above) have densities from 0 to 1.9 in steps of 0.1. When printed in a properly calibrated system they should closely match the Q-13 because typical paper adds about 0.05 to the density. taken from http://www.normankoren.com/makingfineprints4.html AND The eye easily detects density differences as low as 0.02 in the average highlight density, but can detect density differences only on the order of 0.20 in the average shadow density." About the A, M and B patches the Q13 specification says: "The patches identified with the designations A, M and B are used in KODAK Three- Aim Point Control methods for reproducing color reflection copy with traditional masking and color separations procedures. A, M and B patches correspond with reflection densities of 0.0, 0.70, and 1.60, respectively, which represent average highlight, middletone, and shadow values in color or black-and-white reflection copy." taken from http://www.aim-dtp.net/aim/calibration/middle_gray/ so, my Kodak Q-13 indeed reads .70 at the M point and each step increases or decreases .10 points (with some minor variations + or - ). i print my "digital Q-13" and adjust my densities 0-B (16) in .10 increments. from the last 1/4 of the target, i just adjust until i got what "appeared" to be even separation. i initially tried this several years back when i was using the original quadtones from MIS, and all of my monitor to print issues where gone (assuming my monitor was calibrated, and i was in GOOD lighting when viewing the print). i found that in dim indoor lighting, all i had to do was to print with the 1.8 gamma selected in the Epson driver, as opposed to the 2.2 that i use when adjusting levels. not very scientific, but printing with 1.8 worked in many cases. most often 2.2 looked wonderful to me. with IJC, after i linearized, i would adjust the AIMs point slider until my M (7) patch on my Q-13 file read as close to .70 as could be achieved (+or- a few points). from there, all looked great monitor to print. QTR does not have the option like IJC does (AIM's slider), but seems to offer better control otherwise. (plus i am using a 3800 since my 2200 died) i supposed i could make a PS adjustment layer to apply to the file, flatten it, then print with QTR (once linearized) to achieve the same thing??? is there a better way of handling this? (i know that can be subjective) have i missed the boat entirely and have a very wrong understanding of all the above? any thoughts or help would be appreciated evan