Doepfer

Hang on, so the X input of Ring mod 2 is the output? And the output of Ring mod 1 is patched to the normal output of Ring mod 2, like Ring mod 2 is patched in reverse?



--- On Sat, 10/10/09, achtung_999 <heinrich.himmelwasser@gmail.com> wrote:

From: achtung_999 <heinrich.himmelwasser@gmail.com>
Subject: Re: [Doepfer_a100] Mod-demod - Not quite getting this one?
To: Doepfer_a100@yahoogroups.com
Date: Saturday, October 10, 2009, 3:37 PM






 




    
                  Fast answer without listening to the sound yet..In theory you should have

the upper sum harmonic with the X input as output from the Mod Demod..

So if your sound is a low sine chances are that the difference harmonic is

too low to hear..

Leaving thereby only the sum harmonic and the leakage from the X input...



On Sat, Oct 10, 2009 at 4:23 PM, propane23 <propane23@yahoo. com> wrote:



>

>

> Let me see if i've got this right:

>

> Osc A to Ring mod 1 X input

> Osc B to Ring mod 1 Y input

> Ring mod 1 output to Ring mod 2 X input

> Osc B inverted to Ring mod 2 Y input

>

> I've had a few goes and i can't tell any difference between 'mod demod' and

> just plain two ring mods in series, the following audio has a VCS in the

> patch to switch the Ring mod 2 Y input between inverted and non-inverted on

> each new note on.

>

> http://homepage. ntlworld. com/marieshrewsb ury/ModDemod% 20101009. wav

>

> It sounds just the same? First part is using an LFO in the audio range,

> then i swap patch cables to use a VCO instead, but there is no change on

> alternate notes.

>

>  

>



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